2n^2-2n-242=0

Solution for 2n^2-2n-242=0 equation:

2n^2-2n-242=0

a = 2; b = -2; c = -242;
Δ = b2-4ac
Δ = -22-4·2·(-242)
Δ = 1940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1940}=\sqrt{4*485}=\sqrt{4}*\sqrt{485}=2\sqrt{485}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{485}}{2*2}=\frac{2-2\sqrt{485}}{4}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{485}}{2*2}=\frac{2+2\sqrt{485}}{4}
$